MHT CET · Physics · Laws of Motion
A heavy mass is attached at one end of a thin wire and whirled in a vertical circle. The chances of breaking the wire are maximum when
- A the wire is horizontal.
- B the mass is at the lowest point of the circle.
- C the wire makes an angle of \(60^{\circ}\) with the horizontal.
- D the mass is at the highest point of the circle.
Answer & Solution
Correct Answer
(B) the mass is at the lowest point of the circle.
Step-by-step Solution
Detailed explanation
When the mass is at the lowest point.
Explanation \(\Rightarrow\) The Force acting on the Particles will be maximum in case of the Vertical circle when the Force acting will be in the direction of its tension force of string.
When this situation arises then,
Tension \((\mathrm{T})=\frac{\mathrm{mv}^{2}}{\mathrm{r}}\)
\(\therefore\) Force will be maximum at this position and there will likely be more chances to break.
This case will be there when the mass is at the lowest position.
\(\therefore\) Option (b). is correct.
Explanation \(\Rightarrow\) The Force acting on the Particles will be maximum in case of the Vertical circle when the Force acting will be in the direction of its tension force of string.
When this situation arises then,
Tension \((\mathrm{T})=\frac{\mathrm{mv}^{2}}{\mathrm{r}}\)
\(\therefore\) Force will be maximum at this position and there will likely be more chances to break.
This case will be there when the mass is at the lowest position.
\(\therefore\) Option (b). is correct.
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