MHT CET · Physics · Ray Optics
A glass slab of thickness 4.8 cm is placed on the piece of paper on which an ink dot is marked. By how much distance would an ink dot appear to be raised?
\((\) The refractive index of glass \(=1.5)\)
- A 1.6 cm
- B 2.4 cm
- C 3.2 cm
- D 4.8 cm
Answer & Solution
Correct Answer
(A) 1.6 cm
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} & \mathrm{n}=\frac{\text { Real depth }}{\text { Apparent depth }} \\ 1.5=\frac{4.8}{\mathrm{~d}^{\prime}} \\ \therefore \quad & \mathrm{d}^{\prime}=3.2 \mathrm{~cm}\end{array}\)
\(\therefore \quad \mathrm{h}=\mathrm{d}-\mathrm{d}^{\prime}=4.8-3.2=1.6 \mathrm{~cm}\)
\(\therefore \quad \mathrm{h}=\mathrm{d}-\mathrm{d}^{\prime}=4.8-3.2=1.6 \mathrm{~cm}\)
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