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MHT CET · Physics · Ray Optics

A glass slab has refractive index ' \(\mu\) ' with respect to air and the critical angle for a ray of light in going from glass to air is ' \(\theta\) ' If a ray of light is incident from air on the glass with angle of incidence ' \(\theta\) ', then the corresponding angle of refraction is

  1. A \(\sin ^{-1}\left(\frac{1}{\sqrt{\mu}}\right)\)
  2. B \(\sin ^{-1}\left(\frac{1}{\mu}\right)\)
  3. C \(\sin ^{-1}\left(\frac{1}{\mu^2}\right)\)
  4. D \(90^{\circ}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sin ^{-1}\left(\frac{1}{\mu^2}\right)\)

Step-by-step Solution

Detailed explanation

In the first case \(\theta\) is the critical angel
Hence, \(\sin \theta=\frac{1}{\mu}\)
In the second case, \(\frac{\sin \theta}{\sin r}=\mu\)
\(
\begin{aligned}
& \therefore \sin r=\frac{\sin \theta}{\mu} \\
& \therefore \sin r=\frac{1}{\mu^2} \\
& \therefore \sin r=\left(\frac{1}{\mu^2}\right)
\end{aligned}
\)