MHT CET · Physics · Ray Optics
A glass prism deviates the red and violet rays through \(9^{\circ}\) and \(11^{\circ}\) respectively. A second prism of equal angle deviates them through \(11^{\circ}\) and \(13^{\circ}\) respectively. The ratio of dispersive power of second nrism to first prism is
- A \(5: 6\)
- B \(6: 5\)
- C \(9: 13\)
- D \(13: 9\)
Answer & Solution
Correct Answer
(A) \(5: 6\)
Step-by-step Solution
Detailed explanation
\(\therefore \quad\) Dispersive Power of Prism:
\(
\begin{aligned}
& \omega=\frac{\delta_v-\delta_r}{\delta_y} \\
& \delta_y=\frac{\delta_v+\delta_r}{2}=\frac{11+9}{2}
\end{aligned}
\)
\(\therefore \quad\) For first Prism,
\(
\begin{aligned}
\omega_1 & =\frac{2(11-9)}{11+9} \\
& =\frac{1}{5}
\end{aligned}
\)
For Second Prism:
\(
\begin{aligned}
\omega_2 & =\frac{2(13-11)}{13+11} \\
& =\frac{1}{6}
\end{aligned}
\)
Ratio:
\(
\frac{\omega_2}{\omega_1}=\frac{\frac{1}{6}}{\frac{1}{5}}=\frac{5}{6}
\)
\(\therefore \quad\) The ratio is \(5: 6\).
\(
\begin{aligned}
& \omega=\frac{\delta_v-\delta_r}{\delta_y} \\
& \delta_y=\frac{\delta_v+\delta_r}{2}=\frac{11+9}{2}
\end{aligned}
\)
\(\therefore \quad\) For first Prism,
\(
\begin{aligned}
\omega_1 & =\frac{2(11-9)}{11+9} \\
& =\frac{1}{5}
\end{aligned}
\)
For Second Prism:
\(
\begin{aligned}
\omega_2 & =\frac{2(13-11)}{13+11} \\
& =\frac{1}{6}
\end{aligned}
\)
Ratio:
\(
\frac{\omega_2}{\omega_1}=\frac{\frac{1}{6}}{\frac{1}{5}}=\frac{5}{6}
\)
\(\therefore \quad\) The ratio is \(5: 6\).
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