MHT CET · Physics · Current Electricity
A galvanometer of resistance ' \(G\) ' is shunted by a resistance of \(5 \Omega\). To keep the main current in the circuit unchanged, the resistance to be put in series with the same galvanometer is
- A \(\frac{\mathrm{G}^2}{\mathrm{~S}+\mathrm{G}}\)
- B \(\frac{5 G}{S+G}\)
- C \(\frac{G}{S+G}\)
- D \(\frac{S^2}{S+G}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{G}^2}{\mathrm{~S}+\mathrm{G}}\)
Step-by-step Solution
Detailed explanation
Current will be unchanged if resistance remains same to
\(\begin{aligned} & G=\frac{G S}{G+S}+R \\ & \Rightarrow R=G-\frac{G S}{G+S}=\frac{G^2}{G+S}\end{aligned}\)
\(\begin{aligned} & G=\frac{G S}{G+S}+R \\ & \Rightarrow R=G-\frac{G S}{G+S}=\frac{G^2}{G+S}\end{aligned}\)
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