MHT CET · Physics · Current Electricity
A galvanometer of resistance ' \(G\) ' is shunted by resistance of 'S' ohm. To keep the main current in the circuit unchanged the resistance to be put in series with Galvanometer is
- A \(\frac{\mathrm{G}^2}{\mathrm{~S}+\mathrm{G}}\)
- B \(\frac{\mathrm{G}}{\mathrm{S}+\mathrm{G}}\)
- C \(\frac{\mathrm{S}^2}{\mathrm{G}+\mathrm{S}}\)
- D \(\frac{\mathrm{GS}}{\mathrm{S}+\mathrm{G}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{G}^2}{\mathrm{~S}+\mathrm{G}}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} & \text { Now, } \mathrm{G}=\left(\frac{\mathrm{GS}}{\mathrm{S}+\mathrm{G}}\right)+\mathrm{S}^{\prime} \\ \therefore \quad & \mathrm{G}-\frac{\mathrm{GS}}{\mathrm{S}+\mathrm{G}}=\mathrm{S}^{\prime} \\ \therefore \quad & \mathrm{S}^{\prime}=\frac{\mathrm{G}^2}{\mathrm{~S}+\mathrm{G}}\end{array}\)
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