MHT CET · Physics · Current Electricity
A galvanometer of resistance \(G\) has voltage range \(V_g\). Resistance requirec to convert it to read voltage up to \(V\) is
- A \(\frac{G \cdot V_g}{V}-G\)
- B \(\left(\frac{G+V_g}{V}\right) \cdot G\)
- C \(\left(\frac{V-V_g}{V}\right) \cdot G\)
- D \(G \cdot\left[\frac{V}{V_g}-1\right]\)
Answer & Solution
Correct Answer
(D) \(G \cdot\left[\frac{V}{V_g}-1\right]\)
Step-by-step Solution
Detailed explanation
The correct option is (D).
To convert a galvanometer into a voltmeter we need to connect a large resistor in series.
Consider the following diagram swith usual labels.
Consider the following, net potential drop across the voltmeter:
\(I_g R+l_g G=V\)
On re-writing, \(R=\frac{V}{I_g}-G\), and we know, \(V_g=I_g G\).
Therefore, \(R=G\left(\frac{V}{V_g}-1\right)\)
To convert a galvanometer into a voltmeter we need to connect a large resistor in series.
Consider the following diagram swith usual labels.
Consider the following, net potential drop across the voltmeter:
\(I_g R+l_g G=V\)
On re-writing, \(R=\frac{V}{I_g}-G\), and we know, \(V_g=I_g G\).
Therefore, \(R=G\left(\frac{V}{V_g}-1\right)\)
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