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MHT CET · Physics · Current Electricity

A galvanometer of resistance 30 Ω is connected to a battery of emf 2 V with 1970 Ω resistance in series. A full scale deflection of 20 divisions is obtained in the galvanometer. To reduce the deflection to 10 divisions, the resistance in series required is

  1. A 4030 Ω
  2. B 4000 Ω
  3. C 3970 Ω
  4. D 2000 Ω
Verified Solution

Answer & Solution

Correct Answer

(C) 3970 Ω

Step-by-step Solution

Detailed explanation

i=VReff=V1970+30=22000=1×10-3A=mA
This current provides full scale deflection (i.e. 20 division) In order to limit the deflection 10 divisions,
the resistances needed to connect  can be obtained as
θ=niABk   θ1θ2=i1i2
  θ1 :θ2=2
  i1:i2=2:1
  i2=i12=1×10-32=5×10-4mA
  i=VReff+RsRs=Vi-Reff
=25×10-4-2000
=25×104-2000
=4×103-2000
=2000 Ω
  The resistance of 1970 Ω is to be replaced by 1970+2000=3970 Ω