MHT CET · Physics · Current Electricity
A galvanometer has resistance ' \(G\) ' \(\Omega\) and ' \(I_g\) ' is current flowing through it which produces full scale deflection. ' \(S_1\) ' is the value of shunt which converts it into an ammeter of range 0 to ' \(3 I\) ' and ' \(S_2\) ' is the shunt value which converts it into an ammeter of range 0 to ' \(4 I\) ', the ratio \(S_2: S_1\) is
- A \(\frac{4}{3}\)
- B \(\frac{3 I-I_g}{4 I-I_g}\)
- C \(\frac{3}{4}\)
- D \(\frac{4 I-I_g}{3 I-I_g}\)
Answer & Solution
Correct Answer
(B) \(\frac{3 I-I_g}{4 I-I_g}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & s_1=\frac{I_g G}{3 I-I_g}, s_2=\frac{I_g G}{4 I-I_g} \\ & \therefore \frac{s_2}{s_1}=\frac{3 I-I_g}{4 I-I_g}\end{aligned}\)
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