MHT CET · Physics · Current Electricity
A galvanometer has resistance \(80 \Omega\) and it is shunted with resistance \(20 \Omega\). If \(20 \%\) of the main current flows through galvanometer, then what is the value of main current?
- A 0.2 A
- B 0.8 A
- C 1 A
- D 1.2 A
Answer & Solution
Correct Answer
(C) 1 A
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & I=I_1+I_2 \\ & I_1=0.2 \mathrm{I} \quad \therefore \quad \mathrm{I}_2=0.8 \mathrm{I} \\ & \text { Also, } \mathrm{I}_1 \mathrm{G}=\mathrm{I}_2 \mathrm{~S} \\ \therefore \quad & 0.2 \mathrm{I} \times 80=0.8 \mathrm{I} \times 20 \\ \therefore \quad & \mathrm{I}=1 \mathrm{~A}\end{aligned}\)
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