MHT CET · Physics · Laws of Motion
A force acting on a body of mass 5 Kg is \((4 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}) \mathrm{N}\). If the body is initially at rest then the magnitude of its velocity at the end of 10 second in \(\mathrm{m} / \mathrm{s}\) will be
- A \(3 \sqrt{35}\)
- B \(2 \sqrt{29}\)
- C \(\sqrt{19}\)
- D \(3 \sqrt{23}\)
Answer & Solution
Correct Answer
(B) \(2 \sqrt{29}\)
Step-by-step Solution
Detailed explanation
\(\vec{a} = \frac{\vec{F}}{m} = \frac{(4 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}) \, \mathrm{N}}{5 \, \mathrm{Kg}} = (0.8 \hat{\mathrm{i}}-0.4 \hat{\mathrm{j}}+0.6 \hat{\mathrm{k}}) \, \mathrm{m/s^2}\) \(\vec{v} = \vec{a}t = (0.8 \hat{\mathrm{i}}-0.4 \hat{\mathrm{j}}+0.6 \hat{\mathrm{k}}) \, \mathrm{m/s^2} \times 10 \, \mathrm{s} = (8 \hat{\mathrm{i}}-4 \hat{\mathrm{j}}+6 \hat{\mathrm{k}}) \, \mathrm{m/s}\)
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