MHT CET · Physics · Mechanical Properties of Fluids
A fluid of density ' \(\rho\) ' is flowing through a uniform tube of diameter ' \(\mathrm{d}\) '. The coefficient of viscosity of the fluid is ' \(\eta\) ', then critical velocity of the fluid is
- A inversely proportional to ' \(\eta\) '
- B directly proportional to ' \(\eta\) '
- C directly proportional to 'd'
- D directly proportional to ' \(\rho\) '
Answer & Solution
Correct Answer
(B) directly proportional to ' \(\eta\) '
Step-by-step Solution
Detailed explanation
The equation for critical velocity is given as:
\(\mathrm{v}=\mathrm{k} \frac{\eta}{\rho \mathrm{r}}\)
\(\therefore \quad\) The critical velocity is directly proportional to \(\eta\).
\(\mathrm{v}=\mathrm{k} \frac{\eta}{\rho \mathrm{r}}\)
\(\therefore \quad\) The critical velocity is directly proportional to \(\eta\).
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