MHT CET · Physics · Motion In One Dimension
A driver applies the brakes on seeing the red traffic single \(400 \mathrm{~m}\) ahead. At the time of applying the brakes, the vehicle was moving with \(15 \mathrm{~m} / \mathrm{s}\) and retarding at \(0.3 \mathrm{~m} / \mathrm{s}^2\). The distance covered by the vehicle from the traffic light 1 minute after the application of brakes is
- A 25 m
- B 360 m
- C 40 m
- D 375 m
Answer & Solution
Correct Answer
(C) 40 m
Step-by-step Solution
Detailed explanation
\( \begin{aligned} & \mathrm{u}=15 \mathrm{~m} / \mathrm{s}, \mathrm{a}=-0.3 \mathrm{~m} / \mathrm{s}^2, \mathrm{t}=60 \mathrm{~s} \\ & \mathrm{~s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^2 \\ & =15 \times 60+\frac{1}{2} \times(-0.3) \times(60)^2 \\ & =900-540=360 \mathrm{~m} \end{aligned} \)
Distance from traffic light \(=400-360=40 \mathrm{~m}\)
Distance from traffic light \(=400-360=40 \mathrm{~m}\)
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