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MHT CET · Physics · Wave Optics

A double slit experiment is immersed in water of refractive index \(1 \cdot 33\). The slit separation is \(1 \mathrm{~mm}\), distance between slit and screen is \(1 \cdot 33 \mathrm{~m}\). The slits are illuminated by a light of wavelength \(6300 Å\). The fringewidth is

  1. A \(6.9 \times 10^{-4} \mathrm{~m}\)
  2. B \(6.3 \times 10^{-4} \mathrm{~m}\)
  3. C \(5 \cdot 8 \times 10^{-4} m\)
  4. D 8.6 x \(10^{-4} \mathrm{~m}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(6.3 \times 10^{-4} \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

fringe width \(=X=\frac{\lambda_{W} D}{d}\)
\(\lambda_{w}=\frac{6.3 \times 10^{-7}}{1.33}, \quad D=1 \mathrm{~m}, \quad \mathrm{~d}=10^{-3} \mathrm{~m} \quad\) [on substituting and solving ]
\(X=6.3 \times 10^{-4} \mathrm{~m}\)