MHT CET · Physics · Rotational Motion
A door 1.2 mwide requires a force of \(1 \mathrm{~N}\) to be applied perpendicular at the free end to open or close it. The perpendicular force required at a point 0.2 mdistant from the hinges for opening or closing the door is
- A \(2.4 \mathrm{~N}\)
- B \(3.6 \mathrm{~N}\)
- C \(6.0 \mathrm{~N}\)
- D \(1.2 \mathrm{~N}\)
Answer & Solution
Correct Answer
(C) \(6.0 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
\(\tau\) torque required to open/close the door will remain constant.
\(\begin{aligned} & \tau=r_1 \times F_1=r_2 \times F_2 \\ & 1.2 \times 1=0.2 \times F_2 \\ & \Rightarrow F_2=6 \mathrm{~N}\end{aligned}\)
\(\begin{aligned} & \tau=r_1 \times F_1=r_2 \times F_2 \\ & 1.2 \times 1=0.2 \times F_2 \\ & \Rightarrow F_2=6 \mathrm{~N}\end{aligned}\)
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