MHT CET · Physics · Laws of Motion
A Diwali cracker releases 25 gram gas per second, with a speed of \(400 \mathrm{~ms}^{-1}\) after
explosion. The force exerted by gas on the cracker is
- A 100 dyne
- B 16 newton
- C 10 newton
- D 10,000 dyne
Answer & Solution
Correct Answer
(C) 10 newton
Step-by-step Solution
Detailed explanation
\(\mathrm{F}=\) rate of change of momentum
\(=25 \times 10^{-3} \mathrm{~kg} / \mathrm{s} \times 400 \mathrm{~m} / \mathrm{s}\) \(=10 \mathrm{~N}\)
\(=25 \times 10^{-3} \mathrm{~kg} / \mathrm{s} \times 400 \mathrm{~m} / \mathrm{s}\) \(=10 \mathrm{~N}\)
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