MHT CET · Physics · Rotational Motion

A disc of the moment of inertia $I_{1}$ is rotating in a horizontal plane about an axis passing through a centre and perpendicular to its plane with constant angular speed $ω_{1}$ Another disc of the moment of inertia $I_{2}$ having zero angular speed is placed coaxially on a rotating disc. Now both the disc are rotating with the constant angular speed $ω_{2}$ . The energy lost by the initial rotating disc is

A $\frac{1}{2} [\frac{I_{1} + I_{2}}{I_{1} I_{2}}] ω_{1}^{2}$
B $\frac{1}{2} [\frac{I_{1} I_{2}}{I_{1} - i_{2}}] ω_{1}^{2}$
C $\frac{1}{2} [\frac{I_{1} - I_{2}}{I_{1} I_{2}}] ω_{1}^{2}$
D $\frac{1}{2} [\frac{I_{1} I_{2}}{I_{1} + I_{2}}] ω_{1}^{2}$

Verified Solution

Answer & Solution

Correct Answer

(D) $\frac{1}{2} [\frac{I_{1} I_{2}}{I_{1} + I_{2}}] ω_{1}^{2}$

Step-by-step Solution

Detailed explanation

I_{1} ω_{1} = (I_{1} + I_{2}) ω_{2}

\frac{ω_{2}}{ω_{1}} = \frac{I_{1}}{I_{1} + I_{2}}

E_{1} - E_{2}

= \frac{1}{2} I_{1} ω_{1}^{2} - \frac{1}{2} (I_{1} {+ I}_{2}) ω_{2}^{2}

= \frac{1}{2} ω_{1}^{2} [I_{1} - (I_{1} + I_{2}) \frac{ω_{2}^{2}}{ω_{1}^{2}}]

= \frac{1}{2} ω_{1}^{2} [I_{1} - (I_{1} + I_{2}) \frac{I_{1}^{2}}{{(I_{1} + I_{2})}^{2}}]

= \frac{1}{2} ω_{1}^{2} [\frac{I_{1}^{2} + I_{1} I_{2} - I_{1}^{2}}{I_{1} + I_{2}}] = \frac{1}{2} [\frac{I_{1} I_{2}}{I_{1} + I_{2}}] ω_{1}^{2}

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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