MHT CET · Physics · Thermodynamics
A diatomic gas \(\left(\gamma=\frac{7}{5}\right)\) is compressed adiabatically to volume \(\frac{V_i}{32}\) where \(V_i\) is its initial volume. The initial temperature of the gas is \(T_i\) in Kelvin and the final temperature is '\(xT_{\mathrm{i}}\) '. The value of ' \(x\) ' is
- A \(5\)
- B \(4\)
- C \(3\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(4\)
Step-by-step Solution
Detailed explanation
For adiabatic process:
\(\mathrm{TV}^{\gamma-1}=\) Constant
\(\therefore \quad\) Initially:
\(\mathrm{T}_{\mathrm{i}} \mathrm{V}^{\frac{7}{5}-1}=\)Constant
\(\therefore \quad\) Final condition:
\(\mathrm{xT}_{\mathrm{f}} \mathrm{V}^{\frac{7}{5}-1}=\) Constant
So,
\(\mathrm{T}_{\mathrm{i}} \mathrm{V}^{\frac{7}{5}-1}=\mathrm{xT}_{\mathrm{f}} \mathrm{V}^{\frac{7}{5}-1}\)
\(\mathrm{TV}^{\frac{2}{5}}=\mathrm{xT}\left(\frac{\mathrm{V}}{32}\right)^{\frac{2}{5}}\)
\(x=4\)
\(\mathrm{TV}^{\gamma-1}=\) Constant
\(\therefore \quad\) Initially:
\(\mathrm{T}_{\mathrm{i}} \mathrm{V}^{\frac{7}{5}-1}=\)Constant
\(\therefore \quad\) Final condition:
\(\mathrm{xT}_{\mathrm{f}} \mathrm{V}^{\frac{7}{5}-1}=\) Constant
So,
\(\mathrm{T}_{\mathrm{i}} \mathrm{V}^{\frac{7}{5}-1}=\mathrm{xT}_{\mathrm{f}} \mathrm{V}^{\frac{7}{5}-1}\)
\(\mathrm{TV}^{\frac{2}{5}}=\mathrm{xT}\left(\frac{\mathrm{V}}{32}\right)^{\frac{2}{5}}\)
\(x=4\)
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