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MHT CET · Physics · Waves and Sound

A cylindrical tube open at both ends, has a vibrating air column of fundamental frequency ' \(\mathrm{f}\) ' in air. The tube is dipped vertically in water so that half of its is in water. The fundamental frequency of the vibrating air column is now

  1. A f
  2. B \(\frac{\mathrm{f}}{2}\)
  3. C \(\frac{3 \mathrm{f}}{2}\)
  4. D 2f
Verified Solution

Answer & Solution

Correct Answer

(A) f

Step-by-step Solution

Detailed explanation



\(v=\lambda f\)
Fundamental frequency's \(\lambda=\frac{v}{f} \Rightarrow f_0=\frac{v}{2 L}=f\)
If the tube is dipped half into liquid then it acts as if closed at \(\frac{\mathrm{L}}{2}\).
See figure


The frequency can be written as \(\mathrm{f}_{\mathrm{c}}=\frac{\mathrm{v}}{\lambda_1}=\frac{\mathrm{v}}{2 \mathrm{~L}}=\mathrm{f}\)
\(\therefore\) Fundamental frequency would remain the same ' \(\mathrm{f}\) '.