MHT CET · Physics · Waves and Sound
A cylindrical tube open at both ends, has a vibrating air column of fundamental frequency ' \(\mathrm{f}\) ' in air. The tube is dipped vertically in water so that half of its is in water. The fundamental frequency of the vibrating air column is now
- A f
- B \(\frac{\mathrm{f}}{2}\)
- C \(\frac{3 \mathrm{f}}{2}\)
- D 2f
Answer & Solution
Correct Answer
(A) f
Step-by-step Solution
Detailed explanation

\(v=\lambda f\)
Fundamental frequency's \(\lambda=\frac{v}{f} \Rightarrow f_0=\frac{v}{2 L}=f\)
If the tube is dipped half into liquid then it acts as if closed at \(\frac{\mathrm{L}}{2}\).
See figure

The frequency can be written as \(\mathrm{f}_{\mathrm{c}}=\frac{\mathrm{v}}{\lambda_1}=\frac{\mathrm{v}}{2 \mathrm{~L}}=\mathrm{f}\)
\(\therefore\) Fundamental frequency would remain the same ' \(\mathrm{f}\) '.
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