MHT CET · Physics · Alternating Current
A current of \(5 \mathrm{~A}\) is flowing at \(220 \mathrm{~V}\) in the primary coil of transformer. If the voltage produced in the secondary coil is \(2200 \mathrm{~V}\) and \(50 \%\) of power is lost, then the current in secondary will be
- A 2.5 A
- B 0.5 A
- C 0.25 A
- D 5 A
Answer & Solution
Correct Answer
(C) 0.25 A
Step-by-step Solution
Detailed explanation
Let \(I\) be the current flowing through secondary coil.
Current on primary (input) coil \(i=5 \mathrm{~A}\)
Voltage in primary coil \(V=220 \mathrm{~V}\)
Voltage in secondary coil \(V^{\prime}=2200 \mathrm{~V}\)
Considering only \(50 \%\) power is transmitted:
\(\begin{aligned}
& 0.5(\mathrm{Vi})=V^{\prime} I \\
& \therefore 0.5 \times 220 \times 5=2200 \times I \\
& \Rightarrow I=0.25 \mathrm{~A}
\end{aligned}\)
Current on primary (input) coil \(i=5 \mathrm{~A}\)
Voltage in primary coil \(V=220 \mathrm{~V}\)
Voltage in secondary coil \(V^{\prime}=2200 \mathrm{~V}\)
Considering only \(50 \%\) power is transmitted:
\(\begin{aligned}
& 0.5(\mathrm{Vi})=V^{\prime} I \\
& \therefore 0.5 \times 220 \times 5=2200 \times I \\
& \Rightarrow I=0.25 \mathrm{~A}
\end{aligned}\)
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