MHT CET · Physics · Electromagnetic Induction
A current of 0.5 A is passed through winding of a long solenoid having 400 turns. The magnetic flux linked with each turn is \(3 \times 10^{-3} \mathrm{~Wb}\). The self inductance of the solenoid is
- A 2.4 H
- B 2.0 H
- C 1.2 H
- D 0.6 H
Answer & Solution
Correct Answer
(A) 2.4 H
Step-by-step Solution
Detailed explanation
Self inductance, \(L=\frac{N \phi}{i}\)
\(\therefore \quad \mathrm{L}=\frac{400 \times 3 \times 10^{-3}}{0.5}=\frac{1200 \times 10^{-3}}{0.5}=2.4 \mathrm{H}\)
\(\therefore \quad \mathrm{L}=\frac{400 \times 3 \times 10^{-3}}{0.5}=\frac{1200 \times 10^{-3}}{0.5}=2.4 \mathrm{H}\)
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