MHT CET · Physics · Electromagnetic Induction
A current ' \(I\) ' produces a magnetic flux ' \(\phi\) ' per turn in a coil of ' \(n\) ' turns. Self-inductance of the coil is ' \(L\) '. The relation between them is
- A \(\mathrm{nLI}=\phi\)
- B \(\frac{\mathrm{nL}}{\mathrm{I}}=\phi\)
- C \(\frac{\mathrm{LI}}{\mathrm{n}^2}=\phi\)
- D \(\frac{\mathrm{LI}}{\mathrm{n}}=\phi\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{LI}}{\mathrm{n}}=\phi\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{n} \phi=\mathrm{LI} \\ & \therefore \frac{\mathrm{LI}}{\mathrm{n}}=\phi\end{aligned}\)
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