MHT CET · Physics · Rotational Motion
A constant torque of \(200 \mathrm{~N}\) turns a flywheel, which is at rest, about an axis through its centre and perpendicular to its plane. If its moment of inertia is \(50 \mathrm{~kg}-\mathrm{m}^{2}\), then in 4 second, what will be change in its angular momentum?
- A \(800 \mathrm{~kg}-\mathrm{m}^{2} / \mathrm{s}\)
- B \(200 \mathrm{~kg}-\mathrm{m}^{2} / \mathrm{s}\)
- C \(40 \mathrm{~kg}-\mathrm{m}^{2} / \mathrm{s}\)
- D \(20 \mathrm{~kg}-\mathrm{m}^{2} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(800 \mathrm{~kg}-\mathrm{m}^{2} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
Change in angular momentum \(=\tau . t\)
\(=200 \times 4=800 \mathrm{~kg} \mathrm{~m}^{2} / \mathrm{s}\)
\(=200 \times 4=800 \mathrm{~kg} \mathrm{~m}^{2} / \mathrm{s}\)
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