MHT CET · Physics · Electrostatics
A conducting sphere of radius ' \(R\) ' is given a charge ' \(Q\) ' uniformly. The electric field and the electric potential at the centre of the sphere are respectively [ \(\epsilon_0=\) permittivity of free space]
- A zero and \(\frac{Q}{4 \pi \epsilon_0 R}\)
- B \(\frac{Q}{4 \pi \epsilon_0 R^2}\) and zero
- C \(\frac{Q}{4 \pi \epsilon_0 R}\) and \(\frac{Q}{4 \pi \epsilon_0 R^2}\)
- D zero and zero
Answer & Solution
Correct Answer
(A) zero and \(\frac{Q}{4 \pi \epsilon_0 R}\)
Step-by-step Solution
Detailed explanation
Electric field at the center of a conducting sphere: \( E = 0 \) Electric potential at the center of a conducting sphere: \( V = \frac{Q}{4 \pi \epsilon_0 R} \)
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