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MHT CET · Physics · Ray Optics

A concave mirror of focal length ' \(f\) ' produces an image ' \(n\) ' time the size of the object. If the image is real, then the distance of the object from the mirror is

  1. A \((\mathrm{n}-1) \mathrm{f}\)
  2. B \(\left(\frac{n-1}{n}\right) \mathrm{f}\)
  3. C \(\left(\frac{\mathrm{n}+1}{\mathrm{n}}\right) \mathrm{f}\)
  4. D \((\mathrm{n}+1) \mathrm{f}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\left(\frac{\mathrm{n}+1}{\mathrm{n}}\right) \mathrm{f}\)

Step-by-step Solution

Detailed explanation

As the image is real and inverted Magnification,
\(-\mathrm{n}=\frac{-\mathrm{v}}{\mathrm{u}}\) where \(\mathrm{u}=\) distance of the object
\(\therefore \quad v=n u\)
By mirror formula,
\(\begin{array}{ll}
& \frac{1}{\mathrm{f}}=\frac{1}{\mathrm{v}}+\frac{1}{\mathrm{u}} \\
\therefore & \frac{1}{\mathrm{f}}=\frac{1}{\mathrm{nu}}+\frac{1}{\mathrm{u}} \\
\therefore \quad & \mathrm{u}=\left(\frac{\mathrm{n}+1}{\mathrm{n}}\right) \mathrm{f}
\end{array}\)