MHT CET · Physics · Oscillations

A coin is placed on the horizontal plate. Plate performs S.H.M. vertically with
angular frequency ' \(\omega^{\prime}\). The amplitude (A) of oscillations is gradually increased.
The coin will lose contact with plate for the first time when amplitude is
\((\mathrm{g}=\) acceleration due to gravity \()\)

A \(\frac{\mathrm{g}}{\omega^{2}}\)
B zero
C \(\frac{\omega^{2}}{\mathrm{~g}}\)
D \(\frac{\mathrm{A}}{2}\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\mathrm{g}}{\omega^{2}}\)

Step-by-step Solution

Detailed explanation

(D)
The coin will lose contact with the plate when its acceleration in downward direction just exceeds acceleration due to gravity.
\(\begin{array}{l}
\therefore \omega^{2} \mathrm{x}=\mathrm{g} \\
\therefore \mathrm{x} \quad=\frac{\mathrm{g}}{\omega^{2}}
\end{array}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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