MHT CET · Physics · Electromagnetic Induction
A coil of wire of radius ' \(r\) ' has 600 turns and a self-inductance of 108 mH . The self-inductance of a coil with same radius and 500 turns is
- A 80 mH
- B 75 mH
- C 108 mH
- D 90 MH
Answer & Solution
Correct Answer
(B) 75 mH
Step-by-step Solution
Detailed explanation
\(L \propto N^2 \implies \frac{L_2}{L_1} = \left(\frac{N_2}{N_1}\right)^2\) \(L_2 = L_1 \left(\frac{N_2}{N_1}\right)^2 = 108 \text{ mH} \left(\frac{500}{600}\right)^2 = 108 \times \left(\frac{5}{6}\right)^2 = 108 \times \frac{25}{36} = 3 \times 25 = 75 \text{ mH}\)
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