MHT CET · Physics · Electromagnetic Induction
A coil of resistance \(5 \Omega\) and inductance \(4 \mathrm{H}\) is connected to a \(10 \mathrm{~V}\) battery. The energy stored in the coil
- A \(0.8 \mathrm{~J}\)
- B \(8 \mathrm{~J}\)
- C \(16 \mathrm{~J}\)
- D \(4 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(8 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Stored energy, \(U=\frac{1}{2} L i^{2}=\frac{1}{2} L\left(\frac{E}{R}\right)^{2}\)
Here, \(E=10 \mathrm{~V}, L=4 \mathrm{H}\) and \(R=5 \Omega\)
\(\therefore\)
\(U=\frac{1}{2} \times 4 \times\left(\frac{10}{5}\right)^{2} \mathrm{~J}=8 \mathrm{~J}\)
Here, \(E=10 \mathrm{~V}, L=4 \mathrm{H}\) and \(R=5 \Omega\)
\(\therefore\)
\(U=\frac{1}{2} \times 4 \times\left(\frac{10}{5}\right)^{2} \mathrm{~J}=8 \mathrm{~J}\)
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