MHT CET · Physics · Alternating Current
A coil of resistance \(450 \Omega\) and self - inductance 1.5 henry is connected to an a.c. source of frequency \(\frac{150}{\pi} \mathrm{~Hz}\). The phase difference between voltage and current is
- A \(\tan ^{-1}(0 \cdot 5)\)
- B \(\tan ^{-1}(1)\)
- C \(\tan ^{-1}(1 \cdot 5)\)
- D \(\tan ^{-1}(2 \cdot 0)\)
Answer & Solution
Correct Answer
(B) \(\tan ^{-1}(1)\)
Step-by-step Solution
Detailed explanation
\(X_L = 2 \pi f L = 2 \pi \left(\frac{150}{\pi}\right) (1.5) = 450 \, \Omega\) \(\tan \phi = \frac{X_L}{R} = \frac{450}{450} = 1\)
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