MHT CET · Physics · Electromagnetic Induction
A coil of radius ' \(r\) ' is placed on another coil (whose radius is \(\mathrm{R}\) and current flowing through it is changing) so that their centres coincide \((\mathrm{R} \gg \mathrm{r})\). If both the coils are coplanar then the mutual inductance between them is ( \(\mu_0=\) permeability of free space)
- A \(\frac{\mu_0 \pi R^2}{2 r}\)
- B \(\frac{\mu_0 \pi \mathrm{r}^2}{2 \mathrm{R}}\)
- C \(\frac{\mu_0 \pi r^2}{R}\)
- D \(\frac{\mu_0 \pi R^2}{r}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mu_0 \pi \mathrm{r}^2}{2 \mathrm{R}}\)
Step-by-step Solution
Detailed explanation
Magnetic field, \(B=\frac{\mu_0 I}{2 R}\)
Flux passing through the coil,
\(
\begin{aligned}
\phi & =\mathrm{B} \times \pi \mathrm{r}^2 \\
\therefore \phi & =\frac{\mu_0 \mathrm{I}}{2 \mathrm{R}} \times \pi \mathrm{r}^2
\end{aligned}
\)
Mutual Inductance, \(/ \mathrm{M}=\frac{\phi}{\mathrm{I}}\)
\(
\therefore M=\frac{\frac{\mu_0 I}{2 R} \times \pi r^2}{I}=\frac{\mu_0 \pi r^2}{2 R}
\)
Flux passing through the coil,
\(
\begin{aligned}
\phi & =\mathrm{B} \times \pi \mathrm{r}^2 \\
\therefore \phi & =\frac{\mu_0 \mathrm{I}}{2 \mathrm{R}} \times \pi \mathrm{r}^2
\end{aligned}
\)
Mutual Inductance, \(/ \mathrm{M}=\frac{\phi}{\mathrm{I}}\)
\(
\therefore M=\frac{\frac{\mu_0 I}{2 R} \times \pi r^2}{I}=\frac{\mu_0 \pi r^2}{2 R}
\)
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