MHT CET · Physics · Alternating Current
A coil having an inductance of \(\frac{1}{\pi} H\) is connected in series with a resistance of \(300 \Omega\). If A.C. source \((20 \mathrm{~V}-200 \mathrm{~Hz})\) is connected across the combination, the phase angle between voltage and current is
- A \(\tan ^{-1}\left(\frac{4}{5}\right)\)
- B \(\tan ^{-1}\left(\frac{4}{3}\right)\)
- C \(\tan ^{-1}\left(\frac{5}{4}\right)\)
- D \(\tan ^{-1}\left(\frac{3}{4}\right)\)
Answer & Solution
Correct Answer
(B) \(\tan ^{-1}\left(\frac{4}{3}\right)\)
Step-by-step Solution
Detailed explanation
For LR circuit:
Phase angle \(\tan \phi=\frac{\omega L}{R}=\frac{2 \pi \times 200}{300} \times \frac{1}{\pi}=\frac{4}{3}\)
\(\therefore \phi=\tan ^{-1} \frac{4}{3}\)
Phase angle \(\tan \phi=\frac{\omega L}{R}=\frac{2 \pi \times 200}{300} \times \frac{1}{\pi}=\frac{4}{3}\)
\(\therefore \phi=\tan ^{-1} \frac{4}{3}\)
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