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MHT CET · Physics · Magnetic Effects of Current

A coil having 9 turns carrying current produces magnetic field \(\mathrm{B}_1\) at the centre. Now that coil is rewounded into 3 turns carrying same current. Then magnetic field at the centre \(B_2\) is

  1. A \(\frac{\mathrm{B}_1}{9}\)
  2. B \(9 \mathrm{~B}_1\)
  3. C \(3 \mathrm{~B}_1\)
  4. D \(\frac{\mathrm{B}_1}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\mathrm{B}_1}{9}\)

Step-by-step Solution

Detailed explanation

\(N_1 R_1 = N_2 R_2 \implies 9 R_1 = 3 R_2 \implies R_2 = 3 R_1\) \(B = \frac{\mu_0 N I}{2R}\)