MHT CET · Physics · Waves and Sound
A closed organ pipe and an open organ pipe have their first overtones identical in
frequency. Their lengths are in the ratio
- A \(3: 4\)
- B \(2: 3\)
- C \(4: 5\)
- D \(1: 2\)
Answer & Solution
Correct Answer
(A) \(3: 4\)
Step-by-step Solution
Detailed explanation
First overtone of a closed pipe is given by
\(
\mathrm{f}=\frac{3 \mathrm{~V}}{4 \ell}
\)
First overtone of an open pipe is given by
\(
\mathrm{f}^{\prime}=\frac{\mathrm{V}}{\ell^{\prime}}
\)
Since \(\mathrm{f}=\mathrm{f}^{\prime}, \quad \frac{3 \mathrm{~V}}{4 \ell}=\frac{\mathrm{V}}{\ell^{\prime}}\)
\(
\therefore \frac{\ell}{\ell^{\prime}}=\frac{3}{4}
\)
\(
\mathrm{f}=\frac{3 \mathrm{~V}}{4 \ell}
\)
First overtone of an open pipe is given by
\(
\mathrm{f}^{\prime}=\frac{\mathrm{V}}{\ell^{\prime}}
\)
Since \(\mathrm{f}=\mathrm{f}^{\prime}, \quad \frac{3 \mathrm{~V}}{4 \ell}=\frac{\mathrm{V}}{\ell^{\prime}}\)
\(
\therefore \frac{\ell}{\ell^{\prime}}=\frac{3}{4}
\)
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