MHT CET · Physics · Magnetic Effects of Current
A circular coil carrying current has radius ' \(R\) '. The distance from the centre of the coil on the axis where the magnetic induction will be \(\frac{1}{27}\) th to its value at the centre of the coil is
- A \(3 \sqrt{2} \mathrm{R}\)
- B 3 R
- C \(2 \sqrt{2} \mathrm{R}\)
- D 2 R
Answer & Solution
Correct Answer
(C) \(2 \sqrt{2} \mathrm{R}\)
Step-by-step Solution
Detailed explanation
\(B_x = \frac{1}{27} B_c\) \(\frac{\mu_0 I R^2}{2(R^2 + x^2)^{3/2}} = \frac{1}{27} \frac{\mu_0 I}{2R}\)
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