MHT CET · Physics · Magnetic Effects of Current
A charged particle is moving along a magnetic field line. What is the magnetic force acting on the particle? \(\left(\sin 0^{\circ}=0, \sin \frac{\pi}{2}=1\right)\)
- A Opposite to its velocity.
- B Perpendicular to its velocity.
- C Zero.
- D Along its velocity.
Answer & Solution
Correct Answer
(C) Zero.
Step-by-step Solution
Detailed explanation
Magnetic force is given by, \(\mathrm{F}=\mathrm{qvB} \sin \theta\) Where \(\theta\) is the angle between the velocity vector of the charged particle and the direction of the magnetic field.
Since charged particle is moving along a magnetic field line \(\theta=0^{\circ}\).
If \(\theta=0^{\circ}\), then \(F=0\)
\(\ldots\left(\because \sin 0^{\circ}=0\right)\)
Since charged particle is moving along a magnetic field line \(\theta=0^{\circ}\).
If \(\theta=0^{\circ}\), then \(F=0\)
\(\ldots\left(\because \sin 0^{\circ}=0\right)\)
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