MHT CET · Physics · Magnetic Properties of Matter
A charge ' \(q\) ' moves with velocity ' \(v\) ' through electric (E) as well as magnetic field (B). Then the force acting on it is
- A \(\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})\)
- B \(\mathrm{q}(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{v}})\)
- C \(\mathrm{q}(\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{v}})\)
- D \(\overrightarrow{\mathrm{qE}}+\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})\)
Answer & Solution
Correct Answer
(D) \(\overrightarrow{\mathrm{qE}}+\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})\)
Step-by-step Solution
Detailed explanation
Std.12 | Ch-10 | Subtopic-10.2
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