MHT CET · Physics · Electrostatics
A charge \(Q \mu C\) is placed at the centre of a cube. The flux through two opposite faces of the cube is ( \(\epsilon_0=\) permittivity of free space)
- A \(\frac{\mathrm{Q}}{6 \in_0}\)
- B \(\frac{\mathrm{Q}}{3 \epsilon_0}\)
- C \(\frac{\mathrm{Q}}{\epsilon_0}\)
- D \(\frac{\mathrm{Q}}{2 \epsilon_0}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{Q}}{3 \epsilon_0}\)
Step-by-step Solution
Detailed explanation
\(\Phi_{total} = \frac{Q}{\epsilon_0}\) \(\Phi_{2 \text{ faces}} = 2 \times \frac{\Phi_{total}}{6} = 2 \times \frac{1}{6} \times \frac{Q}{\epsilon_0} = \frac{Q}{3 \epsilon_0}\)
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