MHT CET · Physics · Magnetic Effects of Current
A charge of magnitude ' \(2 \mathrm{e}\) ' and mass ' \(4 \mathrm{~m}\) ' is moving in an electric Field E. The acceleration imparted to the above charge is
- A \(\frac{2 \mathrm{~m}}{3 \mathrm{Ee}}\)
- B \(\frac{E e}{2 m}\)
- C \(\frac{2 \mathrm{Ee}}{3 \mathrm{~m}}\)
- D \(\frac{3 \mathrm{~m}}{2 \mathrm{Ee}}\)
Answer & Solution
Correct Answer
(B) \(\frac{E e}{2 m}\)
Step-by-step Solution
Detailed explanation
Force, \(\mathrm{F}=\) charge \(\times\) Electric field \(=2 \mathrm{eE}\)
\(
\text { Acceleration }=\frac{\text { Force }}{\text { Mass }}=\frac{2 \mathrm{eE}}{4 \mathrm{~m}}=\frac{\mathrm{eE}}{2 \mathrm{~m}}
\)
\(
\text { Acceleration }=\frac{\text { Force }}{\text { Mass }}=\frac{2 \mathrm{eE}}{4 \mathrm{~m}}=\frac{\mathrm{eE}}{2 \mathrm{~m}}
\)
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