MHT CET · Physics · Magnetic Effects of Current
A charge moves with velocity ' \(\mathrm{V}\) ' through electric field (E) as well as magnetic field (B). then the force acting on it is
- A \(\mathrm{q}(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{V}})\)
- B \(q(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})\)
- C \(q \overrightarrow{\mathrm{E}}+\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})\)
- D \(\mathrm{q}(\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{V}})\)
Answer & Solution
Correct Answer
(C) \(q \overrightarrow{\mathrm{E}}+\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})\)
Step-by-step Solution
Detailed explanation
Force due to electric field \(\overrightarrow{\mathrm{F}}_{\mathrm{e}}=\mathrm{q} \overrightarrow{\mathrm{E}}\)
Force due to magnetic field \(\overrightarrow{\mathrm{F}}_{\mathrm{m}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})\)
\(\therefore\) Total force \(\overrightarrow{\mathrm{F}}=\mathrm{q} \overrightarrow{\mathrm{E}}+\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})\)
Force due to magnetic field \(\overrightarrow{\mathrm{F}}_{\mathrm{m}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})\)
\(\therefore\) Total force \(\overrightarrow{\mathrm{F}}=\mathrm{q} \overrightarrow{\mathrm{E}}+\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})\)
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