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MHT CET · Physics · Magnetic Effects of Current

A charge moves in a circular path perpendicular to a magnetic field. The time period of the revolution is independent of

  1. A strength of charge.
  2. B magnetic field.
  3. C mass of the charge.
  4. D velocity of the charge.
Verified Solution

Answer & Solution

Correct Answer

(D) velocity of the charge.

Step-by-step Solution

Detailed explanation

The time period of a charged particle undergoing circular motion under uniform perpendicular magnetic field is given by \(T=\frac{2 \pi m}{q B}\)
So, it is independent of velocity.