MHT CET · Physics · Communication System
A carrier wave of peak voltage 16 volt is used to transmit a signal. If the
modulation index is \(75 \%\), the peak voltage of the modulating signal is
- A 6 volt
- B 24 volt
- C 18 volt
- D 12 volt
Answer & Solution
Correct Answer
(D) 12 volt
Step-by-step Solution
Detailed explanation
A carrier wave of peak voltage \(16 \mathrm{~V}\) is used to transmit a signal. If the modulation index is \(75 \%\), the peak voltage of the modulating signal is \(12 \mathrm{~V}\).
Explanation:
Modulation Index
\((\mathrm{MI})=\frac{\text { Peak voltage of modulating signal }\left(\mathrm{V}_{\mathrm{m}}\right)}{\text { Peak voltage of carrier } \operatorname{signal}\left(\mathrm{V}_{\mathrm{C}}\right)}\)
Given, \(\mathrm{Ml}=75 \%\) and \(\mathrm{V}_{\mathrm{C}}=16 \mathrm{~V}\)
\(\therefore \mathrm{V}_{\mathrm{m}}=\mathrm{MI} \times \mathrm{V}_{\mathrm{c}}=\frac{75}{100} \times 16=12 \mathrm{~V}\)
Explanation:
Modulation Index
\((\mathrm{MI})=\frac{\text { Peak voltage of modulating signal }\left(\mathrm{V}_{\mathrm{m}}\right)}{\text { Peak voltage of carrier } \operatorname{signal}\left(\mathrm{V}_{\mathrm{C}}\right)}\)
Given, \(\mathrm{Ml}=75 \%\) and \(\mathrm{V}_{\mathrm{C}}=16 \mathrm{~V}\)
\(\therefore \mathrm{V}_{\mathrm{m}}=\mathrm{MI} \times \mathrm{V}_{\mathrm{c}}=\frac{75}{100} \times 16=12 \mathrm{~V}\)
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