MHT CET · Physics · Thermodynamics
A carnot engine, whose efficiency is \(40 \%\) takes heat from a source maintained at temperature 600 K . It is desired to have an efficiency \(60 \%\), then the intake temperature for the same exhaust (sink) temperature should be
- A 1800 K
- B 1200 K
- C 900 K
- D 600 K
Answer & Solution
Correct Answer
(C) 900 K
Step-by-step Solution
Detailed explanation
For Carnot's engine,
\(\begin{aligned}
& \eta=1-\frac{T_L}{T_H} \\
\therefore \quad & \frac{40}{100}=1-\frac{T_L}{600} \\
& \frac{T_L}{600}=\frac{60}{100} \\
\therefore \quad & T_L=360 \mathrm{~K} \\
\quad & \text { Now, } \frac{60}{100}=1-\frac{360}{T_H} \\
\therefore \quad & \frac{360}{T_H}=\frac{40}{100} \quad \Rightarrow T_H=900 \mathrm{~K}
\end{aligned}\)
\(\begin{aligned}
& \eta=1-\frac{T_L}{T_H} \\
\therefore \quad & \frac{40}{100}=1-\frac{T_L}{600} \\
& \frac{T_L}{600}=\frac{60}{100} \\
\therefore \quad & T_L=360 \mathrm{~K} \\
\quad & \text { Now, } \frac{60}{100}=1-\frac{360}{T_H} \\
\therefore \quad & \frac{360}{T_H}=\frac{40}{100} \quad \Rightarrow T_H=900 \mathrm{~K}
\end{aligned}\)
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