MHT CET · Physics · Thermodynamics
A Carnot engine has efficiency \(\frac{1}{6}\). It becomes \(\frac{1}{3}\), when the temperature of sink is lowered by 57 K . The temperature of the source is
- A 171 K
- B 399 K
- C 342 K
- D 285 K
Answer & Solution
Correct Answer
(C) 342 K
Step-by-step Solution
Detailed explanation
\(\eta_1 = 1 - \frac{T_{c1}}{T_h} \Rightarrow \frac{1}{6} = 1 - \frac{T_{c1}}{T_h} \Rightarrow \frac{T_{c1}}{T_h} = \frac{5}{6}\) \(\eta_2 = 1 - \frac{T_{c2}}{T_h} \Rightarrow \frac{1}{3} = 1 - \frac{T_{c1} - 57}{T_h} \Rightarrow \frac{T_{c1} - 57}{T_h} = \frac{2}{3}\)
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