MHT CET · Physics · Waves and Sound
A car sounding a horn of frequency 1200 Hz passes a stationary observer. The ratio of frequencies of the horn noted by the observer before and after passing the car is \(7: 5\). If the speed of sound is ' \(V\) ', the speed of the car is
- A V
- B \(\frac{\mathrm{V}}{2}\)
- C \(\frac{\mathrm{V}}{6}\)
- D \(\frac{\mathrm{V}}{12}\)
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{V}}{6}\)
Step-by-step Solution
Detailed explanation
\(\frac{f_b}{f_a} = \frac{V/(V - V_s)}{V/(V + V_s)} = \frac{V + V_s}{V - V_s}\) \(\frac{V + V_s}{V - V_s} = \frac{7}{5}\)
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