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MHT CET · Physics · Work Power Energy

A car of mass ' \(m\) ' moving with velocity ' \(u\) ' on a straight road in a straight line, doubles its velocity in time \(t\). the power delivered by the engine of a car for doubling the velocity is

  1. A \(\frac{3 \mathrm{mu}^2}{2 \mathrm{t}}\)
  2. B \(\frac{\mathrm{mu}^2}{2 \mathrm{t}}\)
  3. C \(\frac{2 \mathrm{mu}^2}{\mathrm{t}}\)
  4. D \(\frac{3 \mathrm{mu}^2}{\mathrm{t}}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{3 \mathrm{mu}^2}{2 \mathrm{t}}\)

Step-by-step Solution

Detailed explanation

Initial kinetic energy \(\mathrm{k}_1=\frac{1}{2} \mathrm{mu}^2\)
Final kinetic energy \(\mathrm{k}_2=\frac{1}{2} \mathrm{mu}_2^2=\frac{1}{2} \mathrm{~m}(2 \mathrm{u})^2=\frac{1}{2}\left(4 \mathrm{mu}^2\right)\)
\(\therefore \mathrm{k}_2-\mathrm{k}_1=\frac{3}{2} \mathrm{mu}^2\)
Change in K.E. is work done
Power, \(\mathrm{P}=\frac{\text { workdone }}{\mathrm{t}}=\frac{3 \mathrm{mu}^2}{2 \mathrm{t}}\)