MHT CET · Physics · Mechanical Properties of Fluids
A capillary tube when immersed vertically in water, the rise of water column is upto height \(h_1\) on earth's surface. When this arrangement is taken into a mine of depth ' d ', below earth's surface, the height of the water column is \(h_2\). If \(R\) is the radius of the earth, the ratio \(\frac{h_2}{h_1}\) is
- A \(\frac{\mathrm{R}+\mathrm{d}}{\mathrm{R}}\)
- B \(\frac{\mathrm{R}-\mathrm{d}}{\mathrm{R}}\)
- C \(\frac{R}{R+d}\)
- D \(\frac{\mathrm{R}}{\mathrm{R}-\mathrm{d}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{R}}{\mathrm{R}-\mathrm{d}}\)
Step-by-step Solution
Detailed explanation
\(h \propto \frac{1}{g}\) \(h_1 = \frac{C}{g_1}\)
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