MHT CET · Physics · Mechanical Properties of Fluids
A capillary tube stands with its lower end dipped into liquid for which the angle of contact is \(90^{\circ}\). The liquid will
- A neither rise nor fall.
- B get depressed only.
- C rise only.
- D rise upto the top of the tube.
Answer & Solution
Correct Answer
(A) neither rise nor fall.
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \mathrm{h}=\frac{2 \mathrm{~T} \cos \theta}{\rho g r} \\
& \mathrm{~h}=\frac{2 \mathrm{~T} \cos 90}{\rho g r} \\
& \mathrm{~h}=0^{\quad \ldots\left(\cos 90^{\circ}=0\right)}
\end{aligned}\)
Hence, the liquid will neither rise nor fall.
& \mathrm{h}=\frac{2 \mathrm{~T} \cos \theta}{\rho g r} \\
& \mathrm{~h}=\frac{2 \mathrm{~T} \cos 90}{\rho g r} \\
& \mathrm{~h}=0^{\quad \ldots\left(\cos 90^{\circ}=0\right)}
\end{aligned}\)
Hence, the liquid will neither rise nor fall.
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