MHT CET · Physics · Capacitance
A capacitor is made of a flat plate of area ' \(A\) ' and the second plate has staircase like structure. Width of each stair is ' \(a\) ' and its height is ' \(b\) '. The capacity of the capacitor is

- A \(\frac{\epsilon_0 \mathrm{~A}}{4 \mathrm{~d}}\left[\frac{\mathrm{b}+2 \mathrm{~d}}{\mathrm{~b}}\right]\)
- B \(\frac{\epsilon_0^A}{4 d}\left[\frac{b+2 d}{d+b}\right]\)
- C \(\in_0 A\left[\frac{2 d+b}{d-b}\right]\)
- D \(\frac{\epsilon_0^A}{2 d}\left[\frac{2 d+b}{d+b}\right]\)
Answer & Solution
Correct Answer
(D) \(\frac{\epsilon_0^A}{2 d}\left[\frac{2 d+b}{d+b}\right]\)
Step-by-step Solution
Detailed explanation
Above capacitor can be considered as parallel combination of two capacitors of different width \(\mathrm{d}\) and \(\mathrm{b}+\mathrm{a}\) with each have cross-section \(\frac{\mathrm{A}}{2}\).
\(C=C_1+C_2=\frac{\varepsilon_0\left(\frac{A}{2}\right)}{d}+\frac{\varepsilon_0\left(\frac{A}{2}\right)}{d+b}=\frac{\varepsilon_0 A}{2 d}\left\{\frac{2 d+b}{(d+b)}\right\}\)
\(C=C_1+C_2=\frac{\varepsilon_0\left(\frac{A}{2}\right)}{d}+\frac{\varepsilon_0\left(\frac{A}{2}\right)}{d+b}=\frac{\varepsilon_0 A}{2 d}\left\{\frac{2 d+b}{(d+b)}\right\}\)
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