MHT CET · Physics · Center of Mass Momentum and Collision
A bullet of mass \(20 \mathrm{~g}\) moving with a velocity of \(200 \mathrm{~m} / \mathrm{s}\) strikes a target and is brought to rest in \(\left(\frac{1}{50}\right)^{\text {th }}\) of a second. The impulse and average force of impact are respectively
- A \(2 \mathrm{Ns}, 100 \mathrm{~N}\)
- B \(4 \mathrm{Ns}, 100 \mathrm{~N}\)
- C \(2 \mathrm{Ns}, 200 \mathrm{~N}\)
- D \(4 \mathrm{Ns}, 200 \mathrm{~N}\)
Answer & Solution
Correct Answer
(D) \(4 \mathrm{Ns}, 200 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Impulse: \( J = m(v-u) \) \( J = 0.02 \times (0 - 200) = -4 \mathrm{~Ns} \)
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