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MHT CET · Physics · Motion In Two Dimensions

A body when projected at an angle ' \(\theta\) ' with the horizontal reaches a maximum height ' H '. The time of flight of the body will be ( \(g=\) acceleration due to gravity)

  1. A \(\frac{1}{2} \sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}}\)
  2. B \(\sqrt{\frac{g}{2 H}}\)
  3. C \(2 \sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}}\)
  4. D \(\sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2 \sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}}\)

Step-by-step Solution

Detailed explanation

\( H = \frac{(u \sin \theta)^2}{2g} \) \( u \sin \theta = \sqrt{2gH} \)